给出下列命题:①若向量a·b=a·c, 则向量b=c;②若向量AB·AC>0,则△ABC为锐角三角形;

作者&投稿:庞谭 (若有异议请与网页底部的电邮联系)
判断:若向量AC*向量AB>0,则三角形ABC为锐角三角形~

只能说明 三角形有i个角是 锐角 不能断定是 锐角三角形 错的

解析,
1,AB*BC=|AB|*|BC|*cos(π-∠ABC)<0
故,∠ABC一定是锐角,
但由此,不能断定△ABC就是锐角三角形。
2,AB*BC=|AB|*|BC|*cos(π-∠ABC)>0
那么,∠ABC一定是钝角,
有一个角是钝角的三角形,一定是钝角三角形。
因此,△ABC是钝角三角形。
3,AB*BC=|AB|*|BC|*cos(π-∠ABC)=0
故,∠ABC=π/2,因此,△ABC是直角三角形。

如果,△ABC是直角三角形,∠ABC=90°,
AB*BC=|AB|*|BC|*cos(π-∠ABC)=0
综上可得,△ABC是直角三角形且,∠ABC=90°是向量AB*向量BC=0的充要条件。

第三个命题是正确的。
1.若a为零向量,则无论向量b,c情况如何,原等式都满足。
2.该不等式只能说明向量AB和向量AC的夹角是锐角,不能说明△ABC为锐角三角形。
4.向量|a|·a0是与向量a0方向一致的向量,而向量a有可能与向量a0方向相反。
正确的命题
3.根据条件,用向量加法的三角形法则就可看出:向量a,b与a+b正好构成一个等边三角形,而向量a,-b和a-b正好构成一个等腰钝角三角形,底角即为向量a与向量a-b的夹角,为30°。

无一正确。
①只能得出a与b-c垂直
②只能得出角A为锐角
③夹角为150度
④a与a0可能反向,这时 a=-|a|*a0

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