note+everything+pro破解
“OTE”指代“外部热排气”时在英语中的应用和流行度如何?
4. The Chinese interpretation of "OTE" represents the concept of external thermal exhaust, which is a term commonly used both in professional jargon and everyday communication.5. Its popularity and categorization information suggest that "OTE" plays a significant role within the hardware-...
another \\ other \\ oters \\ the other \\ the others的区别及用法。_百...
其他习惯用法one another, from one…to another, the other day = a few days ago，every other day\/ week\/year， some…, others…，如：I met Mr. Smith in the park the other day.前几天我在公园里碰见了Smith先生。While at the university, he went to the library every other day....
这首歌的名字是什么?
Chairlift - I try to do handstand for you I tried to do handstands for you I tried to do headstands for you Everytime I fell you on yeah everytime I fell I tried to do handstands for you But everytime I fell for you I'm permanently black and blue, permanently blue ...
球初音miku的Calc.的翻唱版本的英文歌词~
when we grow apart,it's destiny it's just how it was supposed to be but i know that i'm not strong enough to accept that so easily each and every single answer that comes my way are sold at too high a price for me to par they rob me of the courage to leave it ...
问个歌名
歌曲名：The Hell Song 演 唱：sum 41 Sum 41 - The Hell Song(live)Everybody's got their problems Everybody says the same things to you It's just a matter how you solve them And knowing how to change the things you've been through I feel I've come to realize How fast ...
...歌曲是什么http:\/\/v.game.sohu.com\/v\/4\/1\/91\/OTE0NjAy
3 布兰妮 斯皮尔斯(Britney Spears)http:\/\/www.google.cn\/music\/song?id=S20f6c8df2bd14ac4&rview=share
铜仁市四环回答： SD卡里,应当有1个类似叫note的文件夹吧.那里边就有
顾苑13317672341问： not后+动词原形吗? - ？
铜仁市四环回答： 如果是完成时,是have\has\had\would have + not + 动词过去分词(动词P.P) 如果是一般现在时,是does\do + not + 原形 如果是现在进行时,是be(am is are) + not + 动词ing形式 如果是被动语态时,是was\were + not + 动词过去分词(P.P)或have\has\had + not + been + 动词过去分词(P.P)或must\could\would\shoud + not + have +P.P
顾苑13317672341问： 设事件ABC的概率都是1/2,P(ABC)=P(非A∩非B∩非C)证明2P(ABC)=P(AB)+P(AC)+P(BC) - 1/2 - ？
铜仁市四环回答： 因为: P(ABC) =P(非A⋂非B ⋂非C) =P(非(A+B+C)) =1 – P(A+B+C) (摩根律) =1 – { P(A)+ P(B)+ P(C)– P(AB)– P(BC)– P(BC)+ P(ABC)} = 1 – 1/2 – 1/2 – 1/2 + P(AB)+ P(BC)+ P(BC)– P(ABC) = – 1/2 + P(AB) + P(BC) + P(BC)- P(ABC) 所以: 2P(ABC)=– 1/2 + P(AB) + P(BC) + P(BC)
顾苑13317672341问： jQuery中div.note>h1+p是什么 - ？
铜仁市四环回答： 这个Jquery选择器选择class是note的div下面的h1后面的所有p标签
顾苑13317672341问： 有4个正整数m,n,p,q满足(7 - m)(7 - n)(7 - p)(7 - q)=4,那么m+n+p+q等于? - ？
铜仁市四环回答： 21或22 4个数 5,5,6,6或者3,6,6,6
顾苑13317672341问： 如果有4个不同的正整数m、n、p、q满足(2013 - m)(2013 - n)(2013 - p)(2013 - q)=4,那么m+n+p+q等于( - ？
铜仁市四环回答： ∵正整数m、n、p、q是4个不同的正整数, ∴(2013-m)(2013-n)(2013-p)(2013-q)=(-1)*1*(-2)*2=4, ∴(2013-m)+(2013-n)+(2013-p)+(2013-q)=-1+1-2+2=0, ∴m+n+p+q=2013*4=8052. 故选D.
顾苑13317672341问： 如果4个不同的正整数m,n,p,g.满足(7 - m)(7 - n)(7 - p)(7 - g)=4 求m+n+p+g的数 - ？
铜仁市四环回答： mnpg分别可为6.8.5.9.所以m+n+p+g=27
顾苑13317672341问： 已知实数p.q.r满足p+q+r=26,1/p+1/q+1/r等于31,求p/q+q/r+r/p+p/r+r/q+q/p的值 - ？
铜仁市四环回答： 因为26*31=(p+q+r)*(1/p+1/q+1/r)=1+1+1+p/q+q/r+r/p+p/r+r/q+q/p 所以p/q+q/r+r/p+p/r+r/q+q/p=26*31-3=803
顾苑13317672341问： 当m= - 6,n= - 8,p=5时,求x和y的值,并观察x,y的关系. (1)x=m+n+( - p); (2) y=m+( - n)+p - ？
铜仁市四环回答： X=m+n-p=(-6)+(-8)+(-5)=-6-8-5=-19 Y=m-n+p=(-6)+(-(-8))+5=-6+8+5=7 Y+2n-2p=m-n+p+2n-2p=m+n-p=X X=-11 Y=7 X=Y+2n-2p
顾苑13317672341问： 如果4个不同的正整数m,n,p,q满足(7 - m)(7 - n)(7 - p)(7 - q)=4,那么m+n+p+q= - ？
铜仁市四环回答： (7-m)(7-n)(7-p)(7-q)这4个都是整数且都不相同,那么只可能是-1,1,-2,2 那么m+n+p+q=7+7+7+7-1+1-2+2=28
