in+an+extended+family
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英语面试常用的句子!
They say Mr. Chen is an honest, hardworking and responsible man who deep ly cares for his family and friends. (他们说陈先生是位诚实、工作努力,负责任 的人,他对家庭和朋友都很关心。) A:They say Mr. Chen is a friendly, sensitive, caring and determined per son.(他们说陈先生是位很友好、...
英语面试常用的对话
A:Good morning. I'm XXX, the manager of the company. What's your name please?(早上好。我是XXX,这个公司的经理。你叫什么名字。)B:Good morning, Miss Pan. My name is XXX. I have come here for an interview by appointment. Nice to meet you.(你好,潘小姐。我叫XXX。我是...
...symbol _peintf :fatal error LNK1120: 1 unresolved exte...
peintf("and we have %d bytes to store it in.\\n",size);是不是拼写错误? printf
叶城县双酚回答: 1、extended family 英 [iksˈtendid ˈfæmili] 美 [ɪkˈstɛndɪd ˈfæməli] n.大家庭,扩大的家庭(如数代同堂的家庭) An extended family enriches life in many ways 大家庭在很多方面会使生活更加丰富多彩. 2、nuclear family 英 [ˈnju:kliə ...
慎吕18211424841问: 向量AB+向量DF+向量CD+向量BC+向量FA - ?
叶城县双酚回答: 向量AB+向量DF+向量CD+向量BC+向量FA=AB+BC+CD+DF+FA=0向量
慎吕18211424841问: 已知函数fx的 定义域为R,对于任意a,b∈都有f(a+b)=fa+fb,且当x>0时,fx<0, - ?
叶城县双酚回答: 令a=b=0 f(0)=2f(0) f(0)=0 令b=-a f(0)=f(a)+f(-a) =0 f(a)=-f(a) 所以f(x)是奇函数 令x2>x1 x2-x1>0 f(x2-x1)<0 f(x2+(-x1)=f(x2)+f(-x1)=f(x2)-f(x1)<0 所以f(x)是减函数 最小值是f(4),最大值是f(-2) f(2)=f(1)+f(1)=-4 f(-2)=-f(2)=4 f(4)=f(2)+f(2)=-8 值域为-8≤f(x)≤4
慎吕18211424841问: f(f(a))<=2.求a的取值范围,fx=x2+x x<0 fx= - x2 x≥0 - ?
叶城县双酚回答: 当 a<0 fa=a^2+a≥0 f(f(a))=-f(a)^2<=0 <2成立 当a=0 fa=0 f(f(a))=0<=2 成立 当a>0 fa=-a^2<0 f(f(a))=fa^2+fa=a^4-a^2<=2 设a^2=t t>0 f(f(a))=t^2-t-2 =(t-2)(t+1)<=0 因为t>0 t+1>0 t-2<=0 t<=2即 a^2<=2 -根号2 =<a=<根号2 前面设的a大于0 所以0<a=<根号2 综上可知 a小于等于根号2 就可以
慎吕18211424841问: A.B.C.D.E.F.G.H表示0 - 9A+B=C D+E=FA FG+H=GF GF=() - ?
叶城县双酚回答: 21.因为A到H表示0-9,D+E=FA,所以FA肯定是十几,所以F肯定是1.所以FG+H=GF即12+9=21,所以GF=21 所以A=3,B=4,C=7,D=5,E=8,F=1,G=2,H=9.A+B=C即3+4=7, D+E=FA即5+8=13,FG+H=GF即12+9=21
慎吕18211424841问: 设F为抛物线x^2=8y的焦点,点A,B,C在此抛物线上,若向量FA+向量FB+向量FC=0,则向量FA的模+向量FB的模+向量FC的模=多少? - ?
叶城县双酚回答:[答案] 焦点F(0,2),准线y=-2,则AF,BF,CF的模分别等于A,B,C到准线的距离. 设A,B,C坐标分别为(x1,y1),(x2,y2),(x3,y3) 因为向量FA+向量FC+向量FC=0,所以F为三角形ABC的重心 由重心定理得(x1+x2+x3)/3=0(0是F横坐标); (y1+y2+y3)/3=2(2...
慎吕18211424841问: 求电影《晚秋》的英文简介 - ?
叶城县双酚回答: A young woman waits in an empty diner outside a lonely bus stop. Pie and a cup of coffee. She touches neither. Every sound of footsteps, she turns. She smiles. "Hi. It's been a long time." Man chu opens with Anna staggering down a suburban ...
慎吕18211424841问: 抛物线y2=8x的焦点为F,过F作直线l交抛物线于A、B两点,设|FA|=m,|FB|=n,则1m+1n=()A.4B.8C.1 - ?
叶城县双酚回答: 抛物线y2=8x的焦点为F(2,0) 设L:y=kx-2k,与y2=8x联立,消去y可得k2x2-(4k2+8)x+4k2=0 设A,B的横坐标分别为x1,x2,则x1+x2=4+8 k2 ,x1x2=4 根据抛物线的定义可知| FA |=m=x1+2,| FB |=n=x2+2 ∴1 m +1 n =1 x1+2 +1 x2+2 = x1+x2+4 x1x2+2(x1+x2)+4 =1 2 故选C.