串联谐振电磁感应加热 线圈L的大小对加热功率的影响

串联谐振电磁感应加热 线圈L的大小对加热功率的影响~

加热功率减小了，原因为：L增加了，感抗也增加了（频率F与电感量L的增加量成开平方的反比，例L加大到4倍，F为0.5倍，感抗加大到2倍）通过线圈电流减小了，当然加热功率会减小（但不会减小到0.5倍）。磁通不会增加的，因为电流会减小。

一般来说线圈短了功率大
因电阻=电阻率*L长度/S截面积
而P=U*I I=U/R
所以截面积不变长度缩短电阻会减小电流会增大
根据以上P就大 反之减小

加热功率减小了，原因为：L增加了，感抗也增加了（频率F与电感量L的增加量成开平方的反比，例L加大到4倍，F为0.5倍，感抗加大到2倍）通过线圈电流减小了，当然加热功率会减小（但不会减小到0.5倍）。磁通不会增加的，因为电流会减小。

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