一句话中能否出现两个名词 比如这句话 His room is a small enough roo

作者&投稿:貂疤 (若有异议请与网页底部的电邮联系)
compared with 和comparing with,对比两个例句!~

非谓语动词做状语时,用主动还是被动取决于句子的主语,如:Compared with his room, my room is even smaller. 句子的主语是my room ,所以用被动。我的房子被比较。Comparing his room, I find my room is even smalle. 主语是I 所以用主动。我进行比较这个动作。注意没有with.所以你给的例句2. Comparing with his room, my room is still a bit of small. 与他的房间比,我的房间还小一点。是个错误的句子。

看看fsolve的源代码:

>> type fsolve

function [x,FVAL,EXITFLAG,OUTPUT,JACOB] = fsolve(FUN,x,options,varargin)
%FSOLVE solves systems of nonlinear equations of several variables.
%
% FSOLVE attempts to solve equations of the form:
%
% F(X)=0 where F and X may be vectors or matrices.
%
% X=FSOLVE(FUN,X0) starts at the matrix X0 and tries to solve the
% equations in FUN. FUN accepts input X and returns a vector (matrix) of
% equation values F evaluated at X.
%
% X=FSOLVE(FUN,X0,OPTIONS) solves the equations with the default optimization
% parameters replaced by values in the structure OPTIONS, an argument
% created with the OPTIMSET function. See OPTIMSET for details. Used
% options are Display, TolX, TolFun, DerivativeCheck, Diagnostics,
% FunValCheck, Jacobian, JacobMult, JacobPattern, LineSearchType,
% NonlEqnAlgorithm, MaxFunEvals, MaxIter, PlotFcns, OutputFcn,
% DiffMinChange and DiffMaxChange, LargeScale, MaxPCGIter,
% PrecondBandWidth, TolPCG, and TypicalX. Use the Jacobian option to
% specify that FUN also returns a second output argument J that is the
% Jacobian matrix at the point X. If FUN returns a vector F of m
% components when X has length n, then J is an m-by-n matrix where J(i,j)
% is the partial derivative of F(i) with respect to x(j). (Note that the
% Jacobian J is the transpose of the gradient of F.)
%
% X = FSOLVE(PROBLEM) solves system defined in PROBLEM. PROBLEM is a
% structure with the function FUN in PROBLEM.objective, the start point
% in PROBLEM.x0, the options structure in PROBLEM.options, and solver
% name 'fsolve' in PROBLEM.solver. Use this syntax to solve at the
% command line a problem exported from OPTIMTOOL. The structure PROBLEM
% must have all the fields.
%
% [X,FVAL]=FSOLVE(FUN,X0,...) returns the value of the equations FUN at X.
%
% [X,FVAL,EXITFLAG]=FSOLVE(FUN,X0,...) returns an EXITFLAG that describes the
% exit condition of FSOLVE. Possible values of EXITFLAG and the corresponding
% exit conditions are
%
% 1 FSOLVE converged to a solution X.
% 2 Change in X smaller than the specified tolerance.
% 3 Change in the residual smaller than the specified tolerance.
% 4 Magnitude of search direction smaller than the specified tolerance.
% 0 Maximum number of function evaluations or iterations reached.
% -1 Algorithm terminated by the output function.
% -2 Algorithm seems to be converging to a point that is not a root.
% -3 Trust region radius became too small.
% -4 Line search cannot sufficiently decrease the residual along the current
% search direction.
%
% [X,FVAL,EXITFLAG,OUTPUT]=FSOLVE(FUN,X0,...) returns a structure OUTPUT
% with the number of iterations taken in OUTPUT.iterations, the number of
% function evaluations in OUTPUT.funcCount, the algorithm used in OUTPUT.algorithm,
% the number of CG iterations (if used) in OUTPUT.cgiterations, the first-order
% optimality (if used) in OUTPUT.firstorderopt, and the exit message in
% OUTPUT.message.
%
% [X,FVAL,EXITFLAG,OUTPUT,JACOB]=FSOLVE(FUN,X0,...) returns the
% Jacobian of FUN at X.
%
% Examples
% FUN can be specified using @:
% x = fsolve(@myfun,[2 3 4],optimset('Display','iter'))
%
% where myfun is a MATLAB function such as:
%
% function F = myfun(x)
% F = sin(x);
%
% FUN can also be an anonymous function:
%
% x = fsolve(@(x) sin(3*x),[1 4],optimset('Display','off'))
%
% If FUN is parameterized, you can use anonymous functions to capture the
% problem-dependent parameters. Suppose you want to solve the system of
% nonlinear equations given in the function myfun, which is parameterized
% by its second argument c. Here myfun is an M-file function such as
%
% function F = myfun(x,c)
% F = [ 2*x(1) - x(2) - exp(c*x(1))
% -x(1) + 2*x(2) - exp(c*x(2))];
%
% To solve the system of equations for a specific value of c, first assign the
% value to c. Then create a one-argument anonymous function that captures
% that value of c and calls myfun with two arguments. Finally, pass this anonymous
% function to FSOLVE:
%
% c = -1; % define parameter first
% x = fsolve(@(x) myfun(x,c),[-5;-5])
%
% See also OPTIMSET, LSQNONLIN, @, INLINE.

% Copyright 1990-2006 The MathWorks, Inc.
% $Revision: 1.41.4.12 $ $Date: 2006/05/19 20:18:49 $

% ------------Initialization----------------

defaultopt = struct('Display','final','LargeScale','off',...
'NonlEqnAlgorithm','dogleg',...
'TolX',1e-6,'TolFun',1e-6,'DerivativeCheck','off',...
'Diagnostics','off','FunValCheck','off',...
'Jacobian','off','JacobMult',[],...% JacobMult set to [] by default
'JacobPattern','sparse(ones(Jrows,Jcols))',...
'MaxFunEvals','100*numberOfVariables',...
'DiffMaxChange',1e-1,'DiffMinChange',1e-8,...
'PrecondBandWidth',0,'TypicalX','ones(numberOfVariables,1)',...
'MaxPCGIter','max(1,floor(numberOfVariables/2))', ...
'TolPCG',0.1,'MaxIter',400,...
'LineSearchType','quadcubic','OutputFcn',[],'PlotFcns',[]);

% If just 'defaults' passed in, return the default options in X
if nargin==1 && nargout <= 1 && isequal(FUN,'defaults')
x = defaultopt;
return
end

if nargin < 3, options=[]; end

% Detect problem structure input
if nargin == 1
if isa(FUN,'struct')
[FUN,x,options] = separateOptimStruct(FUN);
else % Single input and non-structure.
error('optim:fsolve:InputArg','The input to FSOLVE should be either a structure with valid fields or consist of at least two arguments.');
end
end

if nargin == 0
error('optim:fsolve:NotEnoughInputs','FSOLVE requires at least two input arguments.')
end

% Check for non-double inputs
if ~isa(x,'double')
error('optim:fsolve:NonDoubleInput', ...
'FSOLVE only accepts inputs of data type double.')
end

LB = []; UB = [];
xstart=x(:);
numberOfVariables=length(xstart);

large = 'large-scale';
medium = 'medium-scale: line search';
dogleg = 'trust-region dogleg';

switch optimget(options,'Display',defaultopt,'fast')
case {'off','none'}
verbosity = 0;
case 'iter'
verbosity = 2;
case 'final'
verbosity = 1;
case 'testing'
verbosity = Inf;
otherwise
verbosity = 1;
end
diagnostics = isequal(optimget(options,'Diagnostics',defaultopt,'fast'),'on');
gradflag = strcmp(optimget(options,'Jacobian',defaultopt,'fast'),'on');
% 0 means large-scale trust-region, 1 means medium-scale algorithm
mediumflag = strcmp(optimget(options,'LargeScale',defaultopt,'fast'),'off');
funValCheck = strcmp(optimget(options,'FunValCheck',defaultopt,'fast'),'on');
switch optimget(options,'NonlEqnAlgorithm',defaultopt,'fast')
case 'dogleg'
algorithmflag = 1;
case 'lm'
algorithmflag = 2;
case 'gn'
algorithmflag = 3;
otherwise
algorithmflag = 1;
end
mtxmpy = optimget(options,'JacobMult',defaultopt,'fast');
if isequal(mtxmpy,'atamult')
warning('optim:fsolve:NameClash', ...
['Potential function name clash with a Toolbox helper function:
' ...
'Use a name besides ''atamult'' for your JacobMult function to
' ...
'avoid errors or unexpected results.'])
end

% Convert to inline function as needed
if ~isempty(FUN) % will detect empty string, empty matrix, empty cell array
funfcn = lsqfcnchk(FUN,'fsolve',length(varargin),funValCheck,gradflag);
else
error('optim:fsolve:InvalidFUN', ...
['FUN must be a function name, valid string expression, or inline object;
' ...
' or, FUN may be a cell array that contains these type of objects.'])
end

JAC = [];
x(:) = xstart;
switch funfcn{1}
case 'fun'
fuser = feval(funfcn{3},x,varargin{:});
f = fuser(:);
nfun=length(f);
case 'fungrad'
[fuser,JAC] = feval(funfcn{3},x,varargin{:});
f = fuser(:);
nfun=length(f);
case 'fun_then_grad'
fuser = feval(funfcn{3},x,varargin{:});
f = fuser(:);
JAC = feval(funfcn{4},x,varargin{:});
nfun=length(f);
otherwise
error('optim:fsolve:UndefinedCalltype','Undefined calltype in FSOLVE.')
end

if gradflag
% check size of JAC
[Jrows, Jcols]=size(JAC);
if isempty(mtxmpy)
% Not using 'JacobMult' so Jacobian must be correct size
if Jrows~=nfun || Jcols~=numberOfVariables
error('optim:fsolve:InvalidJacobian', ...
['User-defined Jacobian is not the correct size:
' ...
' the Jacobian matrix should be %d-by-%d.'],nfun,numberOfVariables)
end
end
else
Jrows = nfun;
Jcols = numberOfVariables;
end

XDATA = []; YDATA = []; caller = 'fsolve';

% Choose what algorithm to run: determine (i) OUTPUT.algorithm and
% (ii) if and only if OUTPUT.algorithm = medium, also option.LevenbergMarquardt.
% Option LevenbergMarquardt is used internally; it's not user settable. For
% this reason we change this option directly, for speed; users should use
% optimset.
if ~mediumflag
if nfun >= numberOfVariables
% large-scale method and enough equations (as many as variables)
OUTPUT.algorithm = large;
else
% large-scale method and not enough equations - switch to medium-scale algorithm
warning('optim:fsolve:FewerFunsThanVars', ...
['Large-scale method requires at least as many equations as variables;
' ...
' using line-search method instead.'])
OUTPUT.algorithm = medium;
options.LevenbergMarquardt = 'off';
end
else
if algorithmflag == 1 && nfun == numberOfVariables
OUTPUT.algorithm = dogleg;
elseif algorithmflag == 1 && nfun ~= numberOfVariables
warning('optim:fsolve:NonSquareSystem', ...
['Default trust-region dogleg method of FSOLVE cannot
handle non-square systems; ', ...
'using Gauss-Newton method instead.']);
OUTPUT.algorithm = medium;
options.LevenbergMarquardt = 'off';
elseif algorithmflag == 2
OUTPUT.algorithm = medium;
options.LevenbergMarquardt = 'on';
else % algorithmflag == 3
OUTPUT.algorithm = medium;
options.LevenbergMarquardt = 'off';
end
end

if diagnostics > 0
% Do diagnostics on information so far
constflag = 0; gradconstflag = 0; non_eq=0;non_ineq=0;lin_eq=0;lin_ineq=0;
confcn{1}=[];c=[];ceq=[];cGRAD=[];ceqGRAD=[];
hessflag = 0; HESS=[];
diagnose('fsolve',OUTPUT,gradflag,hessflag,constflag,gradconstflag,...
mediumflag,options,defaultopt,xstart,non_eq,...
non_ineq,lin_eq,lin_ineq,LB,UB,funfcn,confcn,f,JAC,HESS,c,ceq,cGRAD,ceqGRAD);

end

% Execute algorithm
if isequal(OUTPUT.algorithm, large)
if ~gradflag
Jstr = optimget(options,'JacobPattern',defaultopt,'fast');
if ischar(Jstr)
if isequal(lower(Jstr),'sparse(ones(jrows,jcols))')
Jstr = sparse(ones(Jrows,Jcols));
else
error('optim:fsolve:InvalidJacobPattern', ...
'Option ''JacobPattern'' must be a matrix if not the default.')
end
end
else
Jstr = [];
end
computeLambda = 0;
[x,FVAL,LAMBDA,JACOB,EXITFLAG,OUTPUT,msg]=...
snls(funfcn,x,LB,UB,verbosity,options,defaultopt,f,JAC,XDATA,YDATA,caller,...
Jstr,computeLambda,varargin{:});
elseif isequal(OUTPUT.algorithm, dogleg)
% trust region dogleg method
Jstr = [];
[x,FVAL,JACOB,EXITFLAG,OUTPUT,msg]=...
trustnleqn(funfcn,x,verbosity,gradflag,options,defaultopt,f,JAC,...
Jstr,varargin{:});
else
% line search (Gauss-Newton or Levenberg-Marquardt)
[x,FVAL,JACOB,EXITFLAG,OUTPUT,msg] = ...
nlsq(funfcn,x,verbosity,options,defaultopt,f,JAC,XDATA,YDATA,caller,varargin{:});
end

Resnorm = FVAL'*FVAL; % assumes FVAL still a vector
if EXITFLAG > 0 % if we think we converged:
if Resnorm > sqrt(optimget(options,'TolFun',defaultopt,'fast'))
OUTPUT.message = ...
sprintf(['Optimizer appears to be converging to a minimum that is not a root:
' ...
'Sum of squares of the function values is > sqrt(options.TolFun).
' ...
'Try again with a new starting point.']);
if verbosity > 0
disp(OUTPUT.message)
end
EXITFLAG = -2;
else
OUTPUT.message = msg;
if verbosity > 0
disp(OUTPUT.message);
end
end
else
OUTPUT.message = msg;
if verbosity > 0
disp(OUTPUT.message);
end
end

% Reset FVAL to shape of the user-function output, fuser
FVAL = reshape(FVAL,size(fuser));

几个名词都行,要看句型!你这个简单句错了!定语从句或者之类的复合句子都可以!

可以,但是有重复的词,一般不这么说
望采纳

这是中式吧,英语一般不这么说。
可以说:His room is very small!

可以 但你的话错了

从句形式可以有


一句话中可以有两个三单吗?
当然可以了。一个主语(三单),两个(或两个以上谓语:都是第三人称单数)如:He gets up early and goes to school on foot.

英语里一个句子中不能有两个动词是什么意思?
即所谓一个句子中不能有两个动词是指一个简单句中不能出现两个动词原型形式的动词。例句:It's too difficult for him to master English in such a short time.他在这么短的时间内掌握英语太难了。这句话中有两个动词,一个是is,一个是master,is在句中作谓语,master作从句中的谓语。

同一个字在一句话中出现两次是病句吗?如:国家统一的会计制度的规定_百 ...
你的这句话不算也行,做为错句也可。但读起来啰嗦换成:国家统一的会计制度规定。这样表达得明白不被误解。同一个字或词在一句话中出现两次不一定是错句。看这个字的作用是什么 如:这个人说:“我知道他不知道”。这不是错句。可以理解成:我知道的是“他不知道”这个事实。当然很少有人这样去...

一句话中可以有两个a吗
一句话中可以有两个a的。a是冠词,可以出现两个及以上的冠词,但是不能两个连在一起用。冠词修饰名词,不能修饰冠词。

英语中,一句话可以出现两个助动词吗
可以的,助动词有have,do,will,would,should等等 比如一个包含从句的句子:They don't know that he has taken the book.同样一句话里也可能出现多种动词,助动词也属于动词的一种。

一句话能出现两个动词吗我在知道中看到一个提问汉译
并列句可以 其它都应该是非谓语

一句话中能否出现2个be动词
这是一个并列句,but作为连词把两个简单句连接起来,前后各自成为一个独立的句子,所以这句话是对的。

我是我。这句话中出现了两个我是语意重复吗?为什么,谢谢
不是语意重复。第一个我是指本身(主语)第二个我是表强调表肯定(强调主语的正确性)

请问一句话里面可以有两个他,而且每个他指向的人不同吗?
一共三个人,是林,丽和李。第一个他是指林,第二个他是指李。

一句话里出现两个主谓的时候要用...?
引导词可以引导一个句子或者是短语。that where when等都是引导词。至于说一个句子中出现两个谓语的话分多种情况:1.有一个动词(其中一个位于吧)做非谓语动词,另外一个做谓语动词。如变成doing格式、to do格式等。There was a long silence,broken only by his heavy breathing,and by the ...

肥城市14775333524: 一句话中能否出现两个名词 比如这句话 His room is a small enough roo -
表紫奈狄: 几个名词都行,要看句型!你这个简单句错了!定语从句或者之类的复合句子都可以!

肥城市14775333524: 一句话中能出现两个名词所有格吗?比如说:They are Melanie's mother's parents. -
表紫奈狄:[答案] 完全可以,在阅读中经常可以见到 It is Mary's neighbour's car 另外的一种是双重属格 a friend of Tom's

肥城市14775333524: 英语中一个句子里,一个单词可以同时有两种词性吗?比如既是介词又是连词,还有,一个句子里面某一成分可以 -
表紫奈狄: 一个单词出现两次可能有两种词性,比如,I book a book.第一个book 是动词,预定;第二个是名词,书. 若一句话里一个单词只出现一次,那它就不可能同时兼顾两种词性了~

肥城市14775333524: 关于一句话里不能出现两个谓语的问题 -
表紫奈狄: 因为这些句子都是从句(即复合句),它们其实都是由两个以上的句子组成的并非一个句子,下面我们来对这两句话进行一下最近单的句子成分划分和分析,就能看出来:I forget (that) you don't like cat => 这句话原本是应该有中间括号里的那个...

肥城市14775333524: 文言文中的一句话中怎样找到什么词活用什么词? -
表紫奈狄: 总体方法是两个相同词性的词放在一起一般有活用,不能修饰的词放在一起有活用 一般最多的是“名词+名词”“名词+动词”“形容词+动词” 举几个例子 1.一个句子中把两个或两个以上的名词放在了一起用 例:楼上的“肉白骨”肉和白骨都是名词,放在一起肉就活用为动词,作“使..长肉”之意 2.一个句子中动词前用了名词,则名词活用为副词 例:则刘病日笃 .“笃”是严重的意思.“日”本应是名词,日子的意思.但是修饰严重,译为副词: 一天天地

肥城市14775333524: 在英语里,一个句子中不能有两个动词是什么意思? -
表紫奈狄: 一个句子中不能有两个动词是指一个句子中不能出现两个谓语,否则不符合英语语法.如果一个句子中出现两个动词,其中一个就必须是非谓语动词或者是从句中的动词. 例句:It's too difficult for him to master English in such a short time. 他在...

肥城市14775333524: The road is covered with snow -
表紫奈狄: 之所以要在这里使用'is',是因为我们讨论的重地是雪掩盖住了道路.如果我们把'is'从句子中取出,那么这句话将会变成 The road covers snow, 道路掩盖住了积雪.Cover,discover, make, 等都是在使用是需要多加注意的词语.比如 I ...

肥城市14775333524: 一个定语从句中 能否同时存在两个that 或两个who? -
表紫奈狄: 当然可以啊,从句里面套从句,比如: I will meet Tim who works for Mr.Gates who is the CEO of Microsoft for 20 years.

肥城市14775333524: 两个"的"能否连用?就是两个形容词同时作一个名词的定语的时候,就像前面这句话里的两个“的”(这里是引用,不是形容词的标志,不算连用哦)一样. -
表紫奈狄:[答案] 两个形容词形容的内容不同时,可以连用,

肥城市14775333524: salvage 作为名词,抢救,为何一个句子中可以出现两个名词? -
表紫奈狄: 名字修饰名词的句子有很多的啊.譬如school bus,classroom blackboard

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