NCE-2 17 Always young
Lesson 17 Always young 青年常驻
My aunt Jennifer is an actress. She must be at least thirty-five years old. In spite of this, she often appears on the stage as a young girl. Jennifer will have to take part in a new play soon. This time, she will be a girl of seventeen. In the play, she must appear in a bright red dress and long black stockings. Last year in another play, she had to wear short socks and a bright, orange-coloured dress. If anyone ever asked her how old she is, she always answers, 'My dear, it must be terrible to be grown up!'
I am Jennifer and I am an actress. I am thirty-six years old but my age is a secret because I always appear on the stage as a teenager. Last year, I had to act a girl who wore short socks and a bright orange-colored dress in a play. Next week, I will act as a girl of seventeen and I must be in a bright red dress and black long socks[=> stockings]. I always say that it is terrible to be grown up if someone asked me how old I am.
我的姑姑詹妮弗是位演员，她至少也有35岁了。尽管如此，她却常在舞台上扮演小姑娘。詹妮弗很快又要参加一个新剧的演出。这一次，她将扮演一个17岁的少女。演出时她必须穿一条鲜红色的裙子和黑色的长筒袜。去年在演另一个剧时，她不得不穿短袜和一件鲜艳的橘红色的衣服。一旦有人问起她有多大年纪，她总是回答：“亲爱的，长成大人真可怕啊！”
My name is Puppy and my wife is Jennifer who is an actress. I am forty while she is thirty-six years old this year. In spite of this, people always take[=> make] mistake that she is my grandgirl when we walk together along, for she appears as a seventeen-year-old girl but I look like an old man. She often shows on stage as a young girl in exaggerated bright dress. I am older one by one year but she is eighteen forver.
(作文时间: 2016年12月30日, 耗时: 100分钟)
(修改时间: 2016年xx月xx日, 耗时: xx分钟)
unfinished
底戚依姆： 首先要把Y的表达式做出来 L1y=-x/1*m+(2-m)/(1+m) L2y=-mx/2-4 如果是平行的话,那么只要X的系数相等,则1/(1+m)=m/2,求解m=-2,m=1这时还不能下结论,还要下一步 相同的话就是后面(2-m)/(1+m)=-4 求解m=-2 综m=1时平行 m=-2时相等
抚远县15371729326： 已知121(x - 1)的平方=64,y 的立方+8=0,求x - y的值 - ？
底戚依姆： ^121(x-1)的平4102方1653=64(x-1)^回2=64/121 x-1=8/11 或答 x-1=-8/11 x=19/11 或 x=3/11 y^3+8=0 y^3=-8 y=-2 x-y= 19/11+2=31/11 或 3/11+2=25/11
抚远县15371729326： 已知x,y是有理数,且满足x+2y - √￣2*y=17+4*2的二次方,求(√￣x+y)的2012次方. - ？
底戚依姆： x,y是有理数,且满足x+2y-y√2=17+4√2=>(x+2y-17)=(4+y)√2=>(x+2y-17)=0;(4+y)=0=>y=-4,x=25=>(√x+y)的2012次方=(√25-4)的2012次方=1的2012次方=1
抚远县15371729326： (x - 2)÷4 - 2y+5=0和3 - x÷3=(y+3)÷6 - ？
底戚依姆： (x-2)÷4-2y+5=0 (x-2)-8y+40=0 x-8y+38=0 8y=x+383-x÷3=(y+3)÷6 18-2x=y+2 y=16-2x 8y=128-16x所以,128-16x=x+38 17x=90 x=17分之90y=16-2*17分之90=17分之92(x,y)=(17分之90,17分之92)
抚远县15371729326： 设X,Y都是有理数,并且X,Y满足X2+Y+Y√2=17 - 4√2.求X+Y的值 - ？
底戚依姆： X2+Y+Y√2=17-4√2(x2+y-17)+(y+4)√2=0(x2+y-17)=-(y+4)√2 可以知道,X,Y都是有理数,所以(x2+y-17)是有理数,同样等式右边也得是有理数.等式右边是-(y-4)√2,要是有理数,只有-(y+4)√2=0 y=-4,所以x2+y-17=0 x2=21 x=21/2
抚远县15371729326： ( - 4 - y)^2 怎么算 - ？
底戚依姆： 等于(-8^-2y)解之得y等于4
抚远县15371729326： 试说明:不论x,y取何值,代数式x^2+6x+y^2 - 4y+15的值总是正数. - ？
底戚依姆： x²+6x+y²-4y+15=x²+6x+9+y²-4y+4+2=(x+3)²+(y-2)²+2 ∵无论x,y取何值 (x+3)²+(y-2)² ≥0 ∴x²+6x+y²-4y+15=(x+3)²+(y-2)²+2>1 ∴不论x,y取何值,代数式x^2+6x+y^2-4y+15的值总是正数
抚远县15371729326： 请帮我做到题 试说明不论X ,Y取何值时代数式X平方加Y平方加4X减6Y加14的值总是正数 - ？
底戚依姆： x^2+y^2+4x-6y+14=x^2+4x+y^2-6y+14=(x+2)^2+(y-3)^2+1, 不论X ,Y取何值,(x+2)^2>=0,(y-3)^2>=0,(x+2)^2+(y-3)^2>=0,(x+2)^2+(y-3)^2+1>=1>0 x^2+y^2+4x-6y+14>0
抚远县15371729326： xy= - 2,x+y=3,求x和y的值 - ？
底戚依姆： xy=-2,x+y=3 x,y是一元二次方程z²-3z-2=0的两根 x=(3+√17)/2,y=(3-√17)/2 或 x=(3-√17)/2,y=(3+√17)/2
抚远县15371729326： x,y为有理数,且满足等式x的平方+2y+y倍的根号2=17 - 4倍的根号2,求x+y的值. - ？
底戚依姆： 由x^2+2y+y*sqrt(2)=17-4sqrt(2),x,y为有理数,故 x^2+2y=17且y=-4,即 {x=5, y=-4},或 {x=-5,y=-4} 故 x+y=1或x+y=-9
