输出万年历

电子万年历输出电压多少？~

你可以把万年历拆开来看一下，里面有一个变压器，上面应该有电压标记，一般是直流12v。变压器不能用电子的，很容易坏的。

import java.text.DateFormatSymbols;
import java.util.Calendar;
import java.util.GregorianCalendar;

public class CalendarTest {

public static void main(String[] args) {
GregorianCalendar d=new GregorianCalendar();
for(int i=0;i<=Calendar.DECEMBER;i++){
d.set(Calendar.MONTH, i);
System.out.println(d.get(Calendar.MONTH)+1+"月");
showMonth(d);
}
}

private static void showMonth(GregorianCalendar d) {
//construct d as current date
int today=d.get(Calendar.DAY_OF_MONTH);
int month=d.get(Calendar.MONTH);
//set d to start date of the month
d.set(Calendar.DAY_OF_MONTH, 1);
int weekday=d.get(Calendar.DAY_OF_WEEK);
//get first day of week(Sunday )
int firstDayOfWeek=d.getFirstDayOfWeek();
//determine the required indentation for the first line
int indenct=0;
while(weekday!=firstDayOfWeek){
indenct++;
d.add(Calendar.DAY_OF_MONTH,-1);
weekday=d.get(Calendar.DAY_OF_WEEK);
}
//print weekday name
String[] weekdayNames=new DateFormatSymbols().getShortWeekdays();
do{
System.out.printf("%4s",weekdayNames[weekday]+"");
d.add(Calendar.DAY_OF_WEEK,1);
weekday=d.get(Calendar.DAY_OF_WEEK);
}while(weekday!=firstDayOfWeek);
System.out.println();
//print space
for(int i=0;i<indenct;i++){
System.out.print("");
}
d.set(Calendar.DAY_OF_MONTH, 1);
do{
//print day
int day=d.get(Calendar.DAY_OF_MONTH);
System.out.printf("%3d",day);
//mark current day with *
if(day==today){
System.out.print("*");
}else{
System.out.print("");
}
//advance d to the next day
d.add(Calendar.DAY_OF_MONTH, 1);
weekday=d.get(Calendar.DAY_OF_WEEK);
//start a new line at the start of the week
if(weekday==firstDayOfWeek){
System.out.println();
}

}while(d.get(Calendar.MONTH)==month);
//the loop exists when d id day 1 of the next money

//print final end of line if necessary
if(weekday!=firstDayOfWeek){
System.out.println();
}
}

}

你试试我尝试过没有问题

以当前电脑时间为基准，显示当前年月的日历
可以按左右方向键，翻到上一月或下一月
可以按上下方向键，翻到上一年或下一年
#include <stdio.h>
#include <conio.h>
#include <stdlib.h>
#include <time.h>

int leap(int year )
{
if ((year %4 == 0) && (year % 100 != 0)
|| (year % 400 == 0))
{
return 1;
}
return 0;
}

void show(int year,int month)
{
const char month_str[][4]={"","Jan","Feb","Mar","Apl",
"May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"};
const int month_day[]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int i,j,wdays,mdays,days;

for(i=1,days=0;i<year;i++)
{
if(leap(i))
{
days += 366;
}
else
{
days += 365;
}
}
for(i=1;i<month;i++)
{
if(i==2 && leap(year))
{
days+=29;
}
else
{
days+=month_day[i];
}
}

printf(" %s (%d)\n",month_str[month],year);
printf(" Mon Tue Wed Thu Fri Sat Sun\n");
wdays = days % 7;
for( j = 0; j < wdays; j++)
{
printf(" ");
}
if(month == 2 && leap(year))
{
mdays=29;
}
else
{
mdays= month_day[month];
}
for(i=1;i<=mdays;i++)
{
if( i > 1 && days % 7 == 0 )
{
printf("\n");
}
printf("%4d",i);
days=days+1;
}
printf("\n---------------------------\n");
}

main()
{
time_t rawtime;
struct tm *info;
int year,month;
char ch;

time ( &rawtime );
info = localtime ( &rawtime );
year =info->tm_year + 1900;
month =info->tm_mon + 1;
while(1)
{
show(year,month);
printf("Left....Prev Month\n");
printf("Right...Next Month\n");
printf("Up......Prev Year\n");
printf("Down....Next Year\n");
printf("Esc.....Exit\n");
ch=getch();
switch(ch)
{
case 27://Ecs
exit(0);
case -32://Navigator
ch=getch();
if(ch==77)
{//Right
year+=(month==12)?1:0;
month=month%12+1;
}
else if(ch==75)
{//Left
year-=(month==1)?1:0;
month=(month-2+12)%12+1;
}
else if(ch==72)
{//Up
year--;
}
else if(ch==80)
{//Down
year++;
}
system("cls");
}
}
}

#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#define X " Sun Mon Tue Wed Thu Fri Sat"

void menu()
{
system("cls");
printf("\nTHIS IS THE MENU OF THE PROGRAM !");
printf("\nYOU CAN CHOOSE THE NUMBER FOR THE FUNCTIOM:");
printf("\n\n");
printf("1 Find the day by year-month-date.\n");
printf("2 Find out whether the year you input is a leap year.\n");
printf("3 Print the calendar of the year you input.\n");
printf("4 Exit.\n\n");
printf("Input your choice:");
}

int getday(int year,int month,int date)
{
int isleap(int year);
int flag,s,i;
int a[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int cont=0;
flag=isleap(year);
if(flag==1)
a[2]++;
for(i=1;i<month;i++)
{
cont=cont+a[i];
}
cont=cont+date;
s=year+1+(year-1)/4+(year-1)/100+(year-1)/400+cont;
return s%7;
}
int isleap(int year)
{
if(year%4==0&&year%100||year%400==0)
return 1;
else
return 0;
}
void print(int n)
{
int i;
for(i=0;i<n;i++) printf(" ");
}
int day(int year)
{
long a,b;
if(year<=2000)
{
a=2000-year;
b=6-(a+a/4-a/100+a/400)%7;
return b;
}
else
{
a=year-2000;
b=(a+1+(a-1)/4-(a-1)/100+(a-1)/400)%7+6;
return b%7;
}
}
void printcalendar(int year)
{
int i,j,k,m,n,f1,f2,d;
int a[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
printf("\nThe calendar of the year %d.\n\n",year);
d=day(year);
if(isleap(year)==1)
a[2]++;
for(i=1;i<=12;i+=2)
{
m=0; n=0; f1=0; f2=0;
switch(i)
{
case 1:printf(" Januray 1 ");break;
case 3:printf(" March 3 ");break;
case 5:printf(" May 5 ");break;
case 7:printf(" July 7 "); break;
case 9:printf(" September 9 ");break;
case 11:printf(" Nevember 11 ");break;
}
print(21);
switch(i+1)
{
case 2:printf(" February 2 "); break;
case 4:printf(" April 4 "); break;
case 6:printf(" June 6 "); break;
case 8:printf(" August 8 "); break;
case 10:printf(" October 10 "); break;
case 12:printf(" December 12"); break;
}
printf("\n");
printf(X);
print(6);
printf(X);
printf("\n");
for(j=0;j<6;j++)
{
if(j==0)
{
print(d*4);
for(k=0;k<7-d;k++)
{
printf("%4d",++m);
}
print(6);
d+=a[i]%7;
d%=7;
print(d*4);
for(k=0;k<7-d;k++)
{
printf("%4d",++n);
}
printf("\n");
}
else
{
for(k=0;k<7;k++)
{
if(m<a[i])
{
printf("%4d",++m);
}
else
{
print(4);
}
if(m==a[i]) f1=1;
}
print(6);
for(k=0;k<7;k++)
{
if(n<a[i+1])
{
printf("%4d",++n);
}
else
{
print(4);
}
if(n==a[i+1]) f2=1;
}
printf("\n");
if(f1&&f2) break;
}
}
d+=a[i+1]%7;
d%=7;
printf(" ");
for(k=0;k<27;k++)
{
printf("=");
}
print(6);
printf(" ");
for(k=0;k<27;k++)
{
printf("=");
}
printf("\n");
if(i==5)
{
printf("Press any key to others!");
getch();
system("cls");
}
}
}
void main()
{
int choice;
int year,month,date;
int day,flag;
char con;
menu();
scanf("%d",&choice);
if(choice==1)
{
r1:system("cls");
printf("\nPlease input the year-month-date(XXXX,XX,XX):");
scanf("%d,%d,%d",&year,&month,&date);
day=getday(year,month,date);
if(day==0)
printf("\n%d-%d-%d is Sunday!\n",year,month,date);
if(day==1)
printf("\n%d-%d-%d is Monday!\n",year,month,date);
if(day==2)
printf("\n%d-%d-%d is Tuesday!\n",year,month,date);
if(day==3)
printf("\n%d-%d-%d is Wednesday!\n",year,month,date);
if(day==4)
printf("\n%d-%d-%d is Thursday!\n",year,month,date);
if(day==5)
printf("\n%d-%d-%d is Friday!\n",year,month,date);
if(day==6)
printf("\n%d-%d-%d is Saturday!\n",year,month,date);
printf("\nContinue...(Y/N)");
con=getch();
if((con=='y')||(con=='Y'))
goto r1;
if((con=='n')||(con=='N'))
main();
}
if(choice==2)
{
r2:system("cls");
printf("\nPlease input the year(XXXX):");
scanf("%d",&year);
flag=isleap(year);
if(flag==1)
printf("\nThe year %d is leap year!\n",year);
if(flag==0)
printf("\nThe year %d is not leap year!\n",year);
printf("\nContinue...(Y/N)");
con=getch();
if((con=='y')||(con=='Y'))
goto r2;
if((con=='n')||(con=='N'))
main();
}
if(choice==3)
{
r3:system("cls");
printf("\nPlease input the year(XXXX):");
scanf("%d",&year);
printcalendar(year);
printf("Continue...(Y/N)");
con=getch();
if((con=='y')||(con=='Y'))
goto r3;
if((con=='n')||(con=='N'))
main();
}
if(choice==4)
{
system("cls");
printf("\nDo you want to Exit?(Y/N)");
con=getch();
if((con=='y')||(con=='Y'))
return;
if((con=='n')||(con=='N'))
main();
}
}

/*
【要求】：

1． 程序运行后，首先在屏幕上显示主菜单：

1． 查询某年某月某日是星期几

2． 查询某年是否是闰年

3． 打印某年的全年日历

4． 退出

2． 在主菜单中输入1后，显示：

“请输入年月日（XXXX，XX，XX）”

运行后输出：XXXX年XX月XX日是星期X，是否继续查询（Y/N）？

如果输入Y，则重新显示 “请输入年月日（XXXX，XX，XX）”，否则回到主菜单。

3． 在主菜单中输入2后，显示：

“请输入要查哪一年？（XXXX）”

运行后输出：XXXX年是（否）是闰年，是否继续查询（Y/N）？

如果输入Y，则重新显示，“请输入要查哪一年？（XXXX）”，否则回到主菜单。

4． 在主菜单中输入3后，显示：

“请输入要打印的年份（XXXX）”

运行后输出XXXX年的日历，格式为：

XXXX

X（月数）

0 1 2 3 4 5 6

S M T W T F S

x x x x x x x

x x x xx xx xx xx

xx xx xx xx xx xx xx

xx xx xx xx xx xx xx

xx xx xx

X（月数）

0 1 2 3 4 5 6

S M T W T F S

x x x x

x x x xx xx xx xx

xx xx xx xx xx xx xx

xx xx xx xx xx xx xx

xx xx xx xx xx

.

运行完后显示：“是否继续打印（Y/N）？”

如果输入Y，则重新显示，“请输入要打印的年份（XXXX）”，否则回到主菜单。

5． 在主菜单中输入4后，显示：“是否要真的退出（Y/N）？”

如果输入Y，结束程序运行，否则重新显示主菜单。
*/

#include "stdio.h"
long int f(int year,int month)
{/*f(年，月)＝年－1，如月<3;否则，f(年，月)＝年*/
if(month<3) return year-1;
else return year;
}

long int g(int month)
{/*g(月)＝月＋13，如月<3;否则，g(月)＝月＋1*/
if(month<3) return month+13;
else return month+1;
}

long int n(int year,int month,int day)
{
/*N=1461*f(年、月)/4+153*g(月)/5+日*/
return 1461L*f(year,month)/4+153L*g(month)/5+day;
}

int w(int year,int month,int day)
{
/*w=(N-621049)%7(0<=w<7)*/
return(int)((n(year,month,day)%7-621049L%7+7)%7);
}

int date[12][6][7];
int day_tbl[ ][12]={{31,28,31,30,31,30,31,31,30,31,30,31},
{31,29,31,30,31,30,31,31,30,31,30,31}};
main()
{int sw,leap,i,j,k,wd,day;
int year;/*年*/
char title[]="SUN MON TUE WED THU FRI SAT";
clrscr();
printf("Please input the year whose calendar you want to know: ");/*输入年*/
scanf("%d%*c",&year);/*输入年份值和掠过值后的回车*/
sw=w(year,1,1);
leap=year%4==0&&year%100||year%400==0;/*判闰年*/
for(i=0;i<12;i++)
for(j=0;j<6;j++)
for(k=0;k<7;k++)
date[i][j][k]=0;/*日期表置0*/
for(i=0;i<12;i++)/*一年十二个月*/
for(wd=0,day=1;day<=day_tbl[leap][i];day++)
{/*将第i＋1月的日期填入日期表*/
date[i][wd][sw]=day;
sw=++sw%7;/*每星期七天，以0至6计数*/
if(sw==0) wd++;/*日期表每七天一行，星期天开始新的一行*/
}

printf("\n|==================The Calendar of Year %d =====================|\n|",year);
for(i=0;i<6;i++)
{/*先测算第i+1月和第i+7月的最大星期数*/
for(wd=0,k=0;k<7;k++)/*日期表的第六行有日期，则wd!=0*/
wd+=date[i][5][k]+date[i+6][5][k];
wd=wd?6:5;
printf("%2d %s %2d %s |\n|",i+1,title,i+7,title);
for(j=0;j<wd;j++)
{
printf(" ");/*输出四个空白符*/
/*左栏为第i+1月，右栏为第i+7月*/
for(k=0;k<7;k++)
if(date[i][j][k])
printf("%4d",date[i][j][k]);
else printf(" ");
printf(" ");/*输出十个空白符*/
for(k=0;k<7;k++)
if(date[i+6][j][k])
printf("%4d",date[i+6][j][k]);
else printf(" ");
printf(" |\n|");
}
/*scanf("%*c");/*键入回车输出下一个月的日历*/

}
puts("=================================================================|");
puts("\n Press any key to quit...");
getch();
}

---

龙湾区15882819829： 输出万年历 - ？
程茗芪胶： 以当前电脑时间为基准,显示当前年月的日历 可以按左右方向键,翻到上一月或下一月 可以按上下方向键,翻到上一年或下一年 #include <stdio.h> #include <conio.h> #include <stdlib.h> #include <time.h> int leap(int year ) { if ((year %4 == 0) && ...

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龙湾区15882819829： C语言万年历 - ？
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程茗芪胶： 已经编译运行确认过. #INCLUDE#INCLUDEINT LEAP(INT); /*判断是否为闰年*/ INT MD(INT M,INT Y); /*返回本月的天数*/ VOID PRTWEEK(VOID); /*输出表头*/ INT FW(INT M,INT Y); /*返回本月一号是星期几*/ VOID PRTMONTH(INT M); ...